X2+2x+x2+3x+10=180

Solution for X2+2x+x2+3x+10=180 equation:

X2+2X+X2+3X+10=180

We move all terms to the left:

X2+2X+X2+3X+10-(180)=0

We add all the numbers together, and all the variables

2X^2+5X-170=0

a = 2; b = 5; c = -170;
Δ = b2-4ac
Δ = 52-4·2·(-170)
Δ = 1385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{1385}}{2*2}=\frac{-5-\sqrt{1385}}{4}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{1385}}{2*2}=\frac{-5+\sqrt{1385}}{4}
$