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X2+24X=25
We move all terms to the left:
X2+24X-(25)=0
We add all the numbers together, and all the variables
X^2+24X-25=0
a = 1; b = 24; c = -25;
Δ = b2-4ac
Δ = 242-4·1·(-25)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-26}{2*1}=\frac{-50}{2} =-25 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+26}{2*1}=\frac{2}{2} =1 $
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