X2+24x-1.6=0

Solution for X2+24x-1.6=0 equation:

X2+24X-1.6=0

We add all the numbers together, and all the variables

X^2+24X-1.6=0

a = 1; b = 24; c = -1.6;
Δ = b2-4ac
Δ = 242-4·1·(-1.6)
Δ = 582.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-\sqrt{582.4}}{2*1}=\frac{-24-\sqrt{582.4}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+\sqrt{582.4}}{2*1}=\frac{-24+\sqrt{582.4}}{2}
$