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X2+2.5X-100=0
We add all the numbers together, and all the variables
X^2+2.5X-100=0
a = 1; b = 2.5; c = -100;
Δ = b2-4ac
Δ = 2.52-4·1·(-100)
Δ = 406.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.5)-\sqrt{406.25}}{2*1}=\frac{-2.5-\sqrt{406.25}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.5)+\sqrt{406.25}}{2*1}=\frac{-2.5+\sqrt{406.25}}{2} $
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