X2+180x-540=0

Solution for X2+180x-540=0 equation:

X2+180X-540=0

We add all the numbers together, and all the variables

X^2+180X-540=0

a = 1; b = 180; c = -540;
Δ = b2-4ac
Δ = 1802-4·1·(-540)
Δ = 34560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{34560}=\sqrt{2304*15}=\sqrt{2304}*\sqrt{15}=48\sqrt{15}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-48\sqrt{15}}{2*1}=\frac{-180-48\sqrt{15}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+48\sqrt{15}}{2*1}=\frac{-180+48\sqrt{15}}{2}
$