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X2+14X-480=0
We add all the numbers together, and all the variables
X^2+14X-480=0
a = 1; b = 14; c = -480;
Δ = b2-4ac
Δ = 142-4·1·(-480)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-46}{2*1}=\frac{-60}{2} =-30 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+46}{2*1}=\frac{32}{2} =16 $
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