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X2+14X-2352=0
We add all the numbers together, and all the variables
X^2+14X-2352=0
a = 1; b = 14; c = -2352;
Δ = b2-4ac
Δ = 142-4·1·(-2352)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9604}=98$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-98}{2*1}=\frac{-112}{2} =-56 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+98}{2*1}=\frac{84}{2} =42 $
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