X2+14x+36=0

Solution for X2+14x+36=0 equation:

X2+14X+36=0

We add all the numbers together, and all the variables

X^2+14X+36=0

a = 1; b = 14; c = +36;
Δ = b2-4ac
Δ = 142-4·1·36
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{13}}{2*1}=\frac{-14-2\sqrt{13}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{13}}{2*1}=\frac{-14+2\sqrt{13}}{2}
$