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X2+10=5X
We move all terms to the left:
X2+10-(5X)=0
We add all the numbers together, and all the variables
X^2-5X+10=0
a = 1; b = -5; c = +10;
Δ = b2-4ac
Δ = -52-4·1·10
Δ = -15
Delta is less than zero, so there is no solution for the equation
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