X/9x-(2x-1)=2

Solution for X/9x-(2x-1)=2 equation:

X/9X-(2X-1)=2

We move all terms to the left:

X/9X-(2X-1)-(2)=0


Domain of the equation: 9X!=0

X!=0/9

X!=0

X∈R


We get rid of parentheses

X/9X-2X+1-2=0

We multiply all the terms by the denominator


X-2X*9X+1*9X-2*9X=0

Wy multiply elements

-18X^2+X+9X-18X=0

We add all the numbers together, and all the variables

-18X^2-8X=0

a = -18; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·(-18)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*-18}=\frac{0}{-36}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*-18}=\frac{16}{-36}
=-4/9
$