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X/6X+20=12+2X
We move all terms to the left:
X/6X+20-(12+2X)=0
Domain of the equation: 6X!=0We add all the numbers together, and all the variables
X!=0/6
X!=0
X∈R
X/6X-(2X+12)+20=0
We get rid of parentheses
X/6X-2X-12+20=0
We multiply all the terms by the denominator
X-2X*6X-12*6X+20*6X=0
Wy multiply elements
-12X^2+X-72X+120X=0
We add all the numbers together, and all the variables
-12X^2+49X=0
a = -12; b = 49; c = 0;
Δ = b2-4ac
Δ = 492-4·(-12)·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-49}{2*-12}=\frac{-98}{-24} =4+1/12 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+49}{2*-12}=\frac{0}{-24} =0 $
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