X/6(3x+2)-5(6x-1)=6(x-3)-5(7x-6)+12x

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Solution for X/6(3x+2)-5(6x-1)=6(x-3)-5(7x-6)+12x equation: 



X/6(3X+2)-5(6X-1)=6(X-3)-5(7X-6)+12X

We move all terms to the left:

X/6(3X+2)-5(6X-1)-(6(X-3)-5(7X-6)+12X)=0



Domain of the equation: 6(3X+2)!=0

X∈R



We multiply parentheses

X/6(3X+2)-30X-(6(X-3)-5(7X-6)+12X)+5=0

We multiply all the terms by the denominator


X-30X*6(3X+2)-((6(X-3)-5(7X-6)+12X))*6(3X+2)+5*6(3X+2)=0



We calculate terms in parentheses: -((6(X-3)-5(7X-6)+12X))*6(3X+2), so:

(6(X-3)-5(7X-6)+12X))*6(3X+2



Wy multiply elements

-180X^2(3-((6(X-3)-5(7X-6)+12X))*6(3X+2)+30X(3+X=0

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