X/5=5+(x-4)/2

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Solution for X/5=5+(x-4)/2 equation: 



X/5=5+(X-4)/2

We move all terms to the left:

X/5-(5+(X-4)/2)=0

We calculate fractions


2X^2/()+(-(5+(X-4)*5)/()=0



We calculate terms in parentheses: +(-(5+(X-4)*5)/(), so:

-(5+(X-4)*5)/(

We multiply all the terms by the denominator


-(5+(X-4)*5)



We calculate terms in parentheses: -(5+(X-4)*5), so:

5+(X-4)*5

determiningTheFunctionDomain
(X-4)*5+5

We multiply parentheses

5X-20+5

We add all the numbers together, and all the variables

5X-15

Back to the equation:

-(5X-15)



We get rid of parentheses

-5X+15

Back to the equation:

+(-5X+15)



We get rid of parentheses

2X^2/()-5X+15=0

We multiply all the terms by the denominator


2X^2-5X*()+15*()=0

We add all the numbers together, and all the variables

2X^2-5X*()=0

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