X/5=(2x+4)/3

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Solution for X/5=(2x+4)/3 equation: 



X/5=(2X+4)/3

We move all terms to the left:

X/5-((2X+4)/3)=0

We calculate fractions


3X^2/()+(-((2X+4)*5)/()=0



We calculate terms in parentheses: +(-((2X+4)*5)/(), so:

-((2X+4)*5)/(

We multiply all the terms by the denominator


-((2X+4)*5)



We calculate terms in parentheses: -((2X+4)*5), so:

(2X+4)*5

We multiply parentheses

10X+20

Back to the equation:

-(10X+20)



We get rid of parentheses

-10X-20

Back to the equation:

+(-10X-20)



We get rid of parentheses

3X^2/()-10X-20=0

We multiply all the terms by the denominator


3X^2-10X*()-20*()=0

We add all the numbers together, and all the variables

3X^2-10X*()=0

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