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X/3=4X/X+3
We move all terms to the left:
X/3-(4X/X+3)=0
Domain of the equation: X+3)!=0We get rid of parentheses
X∈R
X/3-4X/X-3=0
We calculate fractions
X^2/3X+(-12X)/3X-3=0
We multiply all the terms by the denominator
X^2+(-12X)-3*3X=0
Wy multiply elements
X^2+(-12X)-9X=0
We get rid of parentheses
X^2-12X-9X=0
We add all the numbers together, and all the variables
X^2-21X=0
a = 1; b = -21; c = 0;
Δ = b2-4ac
Δ = -212-4·1·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-21}{2*1}=\frac{0}{2} =0 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+21}{2*1}=\frac{42}{2} =21 $
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