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X/2X+4(2X+7)=2X+4
We move all terms to the left:
X/2X+4(2X+7)-(2X+4)=0
Domain of the equation: 2X!=0We multiply parentheses
X!=0/2
X!=0
X∈R
X/2X+8X-(2X+4)+28=0
We get rid of parentheses
X/2X+8X-2X-4+28=0
We multiply all the terms by the denominator
X+8X*2X-2X*2X-4*2X+28*2X=0
Wy multiply elements
16X^2-4X^2+X-8X+56X=0
We add all the numbers together, and all the variables
12X^2+49X=0
a = 12; b = 49; c = 0;
Δ = b2-4ac
Δ = 492-4·12·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-49}{2*12}=\frac{-98}{24} =-4+1/12 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+49}{2*12}=\frac{0}{24} =0 $
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