X/2=5+(x-42)/5

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Solution for X/2=5+(x-42)/5 equation: 



X/2=5+(X-42)/5

We move all terms to the left:

X/2-(5+(X-42)/5)=0

We calculate fractions


5X^2/()+(-(5+(X-42)*2)/()=0



We calculate terms in parentheses: +(-(5+(X-42)*2)/(), so:

-(5+(X-42)*2)/(

We multiply all the terms by the denominator


-(5+(X-42)*2)



We calculate terms in parentheses: -(5+(X-42)*2), so:

5+(X-42)*2

determiningTheFunctionDomain
(X-42)*2+5

We multiply parentheses

2X-84+5

We add all the numbers together, and all the variables

2X-79

Back to the equation:

-(2X-79)



We get rid of parentheses

-2X+79

Back to the equation:

+(-2X+79)



We get rid of parentheses

5X^2/()-2X+79=0

We multiply all the terms by the denominator


5X^2-2X*()+79*()=0

We add all the numbers together, and all the variables

5X^2-2X*()=0

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