X/(2x-4)=3/(x+13)

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Solution for X/(2x-4)=3/(x+13) equation: 



X/(2X-4)=3/(X+13)

We move all terms to the left:

X/(2X-4)-(3/(X+13))=0



Domain of the equation: (2X-4)!=0

We move all terms containing X to the left, all other terms to the right

2X!=4

X!=4/2

X!=2

X∈R





Domain of the equation: (X+13))!=0

X∈R



We calculate fractions


14X^2/((2X-4)*(X+13)))+(-(3*(2X-4))/((2X-4)*(X+13)))=0



We calculate terms in parentheses: -(3*(2X-4))/((2X-4)*(X+13))), so:

3*(2X-4))/((2X-4)*(X+13))

We multiply all the terms by the denominator


3*(2X-4))

We multiply parentheses

6X+

We add all the numbers together, and all the variables

6X

Back to the equation:

-(6X)



We multiply all the terms by the denominator


14X^2-6X*((2X-4)*(X+13)))+(=0

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