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X/(10-3)=5(12X)/(10X)
We move all terms to the left:
X/(10-3)-(5(12X)/(10X))=0
Domain of the equation: 10X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X/7-(+512X/10X)=0
We get rid of parentheses
X/7-512X/10X=0
We calculate fractions
10X^2/70X+(-3584X)/70X=0
We multiply all the terms by the denominator
10X^2+(-3584X)=0
We get rid of parentheses
10X^2-3584X=0
a = 10; b = -3584; c = 0;
Δ = b2-4ac
Δ = -35842-4·10·0
Δ = 12845056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12845056}=3584$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3584)-3584}{2*10}=\frac{0}{20} =0 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3584)+3584}{2*10}=\frac{7168}{20} =358+2/5 $
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