X-6)((x+7)=(x+3)(x-11)

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Solution for X-6)((x+7)=(x+3)(x-11) equation: 



X-6)((X+7)=(X+3)(X-11)

We move all terms to the left:

X-6)((X+7)-((X+3)(X-11))=0

We multiply parentheses ..

-((+X^2-11X+3X-33))+X-6)((X+7)=0



We calculate terms in parentheses: -((+X^2-11X+3X-33)), so:

(+X^2-11X+3X-33)

We get rid of parentheses

X^2-11X+3X-33

We add all the numbers together, and all the variables

X^2-8X-33

Back to the equation:

-(X^2-8X-33)



We add all the numbers together, and all the variables

X-(X^2-8X-33)-6)((X+7)=0

We get rid of parentheses

-X^2+X+8X-6)((X+7)+33=0

We add all the numbers together, and all the variables

-1X^2+9X-6)((X+7)+33=0

We move all terms containing X to the left, all other terms to the right

-1X^2+9X-6)((X+7)=-33

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