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X-3(2X-5)=X-2(2X-4)
We move all terms to the left:
X-3(2X-5)-(X-2(2X-4))=0
We multiply parentheses
X-6X-(X-2(2X-4))+15=0
We calculate terms in parentheses: -(X-2(2X-4)), so:We add all the numbers together, and all the variables
X-2(2X-4)
We multiply parentheses
X-4X+8
We add all the numbers together, and all the variables
-3X+8
Back to the equation:
-(-3X+8)
-5X-(-3X+8)+15=0
We get rid of parentheses
-5X+3X-8+15=0
We add all the numbers together, and all the variables
-2X+7=0
We move all terms containing X to the left, all other terms to the right
-2X=-7
X=-7/-2
X=3+1/2
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