X-2(x+3)=4(2x+3)=4(2x+3)-(x+4)

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Solution for X-2(x+3)=4(2x+3)=4(2x+3)-(x+4) equation: 



X-2(X+3)=4(2X+3)=4(2X+3)-(X+4)

We move all terms to the left:

X-2(X+3)-(4(2X+3))=0

We multiply parentheses

X-2X-(4(2X+3))-6=0



We calculate terms in parentheses: -(4(2X+3)), so:

4(2X+3)

We multiply parentheses

8X+12

Back to the equation:

-(8X+12)



We add all the numbers together, and all the variables

-1X-(8X+12)-6=0

We get rid of parentheses

-1X-8X-12-6=0

We add all the numbers together, and all the variables

-9X-18=0

We move all terms containing X to the left, all other terms to the right

-9X=18

X=18/-9

X=-2

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