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X-10+2X-67+1/2X+5=180
We move all terms to the left:
X-10+2X-67+1/2X+5-(180)=0
Domain of the equation: 2X!=0We add all the numbers together, and all the variables
X!=0/2
X!=0
X∈R
3X+1/2X-252=0
We multiply all the terms by the denominator
3X*2X-252*2X+1=0
Wy multiply elements
6X^2-504X+1=0
a = 6; b = -504; c = +1;
Δ = b2-4ac
Δ = -5042-4·6·1
Δ = 253992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{253992}=\sqrt{4*63498}=\sqrt{4}*\sqrt{63498}=2\sqrt{63498}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-504)-2\sqrt{63498}}{2*6}=\frac{504-2\sqrt{63498}}{12} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-504)+2\sqrt{63498}}{2*6}=\frac{504+2\sqrt{63498}}{12} $
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