X-(2X+5)-5(1-2X)=2(3+4x)-3(x-4)

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Solution for X-(2X+5)-5(1-2X)=2(3+4x)-3(x-4) equation: 



X-(2X+5)-5(1-2X)=2(3+4X)-3(X-4)

We move all terms to the left:

X-(2X+5)-5(1-2X)-(2(3+4X)-3(X-4))=0

We add all the numbers together, and all the variables

X-(2X+5)-5(-2X+1)-(2(4X+3)-3(X-4))=0

We multiply parentheses

X-(2X+5)+10X-(2(4X+3)-3(X-4))-5=0

We get rid of parentheses

X-2X+10X-(2(4X+3)-3(X-4))-5-5=0



We calculate terms in parentheses: -(2(4X+3)-3(X-4)), so:

2(4X+3)-3(X-4)

We multiply parentheses

8X-3X+6+12

We add all the numbers together, and all the variables

5X+18

Back to the equation:

-(5X+18)



We add all the numbers together, and all the variables

9X-(5X+18)-10=0

We get rid of parentheses

9X-5X-18-10=0

We add all the numbers together, and all the variables

4X-28=0

We move all terms containing X to the left, all other terms to the right

4X=28

X=28/4

X=7

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