X+x(x+x)=2x-x+2

Solution for X+x(x+x)=2x-x+2 equation:

X+X(X+X)=2X-X+2

We move all terms to the left:

X+X(X+X)-(2X-X+2)=0

We add all the numbers together, and all the variables

X+X(+2X)-(X+2)=0

We multiply parentheses

2X^2+X-(X+2)=0

We get rid of parentheses

2X^2+X-X-2=0

We add all the numbers together, and all the variables

2X^2-2=0

a = 2; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·2·(-2)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*2}=\frac{-4}{4}
=-1
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*2}=\frac{4}{4}
=1
$