X+9x2=3

Solution for X+9x2=3 equation:

X+9X^2=3

We move all terms to the left:

X+9X^2-(3)=0

a = 9; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·9·(-3)
Δ = 109
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{109}}{2*9}=\frac{-1-\sqrt{109}}{18}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{109}}{2*9}=\frac{-1+\sqrt{109}}{18}
$