X+8/3x-5=x-8/x+8

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Solution for X+8/3x-5=x-8/x+8 equation:



X+8/3X-5=X-8/X+8
We move all terms to the left:
X+8/3X-5-(X-8/X+8)=0
Domain of the equation: 3X!=0
X!=0/3
X!=0
X∈R
Domain of the equation: X+8)!=0
X∈R
We get rid of parentheses
X+8/3X-X+8/X-8-5=0
We calculate fractions
X-X+8X/3X^2+24X/3X^2-8-5=0
We add all the numbers together, and all the variables
8X/3X^2+24X/3X^2-13=0
We multiply all the terms by the denominator
8X+24X-13*3X^2=0
We add all the numbers together, and all the variables
32X-13*3X^2=0
Wy multiply elements
-39X^2+32X=0
a = -39; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·(-39)·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*-39}=\frac{-64}{-78} =32/39 $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*-39}=\frac{0}{-78} =0 $

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