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X+5=10+-(X+5)=10
We move all terms to the left:
X+5-(10+-(X+5))=0
We use the square of the difference formula
X-(10-(X+5))+5=0
We calculate terms in parentheses: -(10-(X+5)), so:We get rid of parentheses
10-(X+5)
determiningTheFunctionDomain -(X+5)+10
We get rid of parentheses
-X-5+10
We add all the numbers together, and all the variables
-1X+5
Back to the equation:
-(-1X+5)
X+1X-5+5=0
We add all the numbers together, and all the variables
2X=0
X=0/2
X=0
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