X+5=(x+5)(x+5)+295

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Solution for X+5=(x+5)(x+5)+295 equation: 



X+5=(X+5)(X+5)+295

We move all terms to the left:

X+5-((X+5)(X+5)+295)=0

We multiply parentheses ..

-((+X^2+5X+5X+25)+295)+X+5=0



We calculate terms in parentheses: -((+X^2+5X+5X+25)+295), so:

(+X^2+5X+5X+25)+295

We get rid of parentheses

X^2+5X+5X+25+295

We add all the numbers together, and all the variables

X^2+10X+320

Back to the equation:

-(X^2+10X+320)



We add all the numbers together, and all the variables

X-(X^2+10X+320)+5=0

We get rid of parentheses

-X^2+X-10X-320+5=0

We add all the numbers together, and all the variables

-1X^2-9X-315=0

a = -1; b = -9; c = -315;
Δ = b2-4ac
Δ = -92-4·(-1)·(-315)
Δ = -1179
Delta is less than zero, so there is no solution for the equation

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