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X+4=1/3X
We move all terms to the left:
X+4-(1/3X)=0
Domain of the equation: 3X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X-(+1/3X)+4=0
We get rid of parentheses
X-1/3X+4=0
We multiply all the terms by the denominator
X*3X+4*3X-1=0
Wy multiply elements
3X^2+12X-1=0
a = 3; b = 12; c = -1;
Δ = b2-4ac
Δ = 122-4·3·(-1)
Δ = 156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{156}=\sqrt{4*39}=\sqrt{4}*\sqrt{39}=2\sqrt{39}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{39}}{2*3}=\frac{-12-2\sqrt{39}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{39}}{2*3}=\frac{-12+2\sqrt{39}}{6} $
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