X+3X+(3x+10)=290

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Solution for X+3X+(3x+10)=290 equation: 



X+3X+(3X+10)=290

We move all terms to the left:

X+3X+(3X+10)-(290)=0

We add all the numbers together, and all the variables

4X+(3X+10)-290=0

We get rid of parentheses

4X+3X+10-290=0

We add all the numbers together, and all the variables

7X-280=0

We move all terms containing X to the left, all other terms to the right

7X=280

X=280/7

X=40

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