X+3(x-4)+28=56

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Solution for X+3(x-4)+28=56 equation: 



X+3(X-4)+28=56

We move all terms to the left:

X+3(X-4)+28-(56)=0

We add all the numbers together, and all the variables

X+3(X-4)-28=0

We multiply parentheses

X+3X-12-28=0

We add all the numbers together, and all the variables

4X-40=0

We move all terms containing X to the left, all other terms to the right

4X=40

X=40/4

X=10

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