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X+3(X+2)=4(X-1)
We move all terms to the left:
X+3(X+2)-(4(X-1))=0
We multiply parentheses
X+3X-(4(X-1))+6=0
We calculate terms in parentheses: -(4(X-1)), so:We add all the numbers together, and all the variables
4(X-1)
We multiply parentheses
4X-4
Back to the equation:
-(4X-4)
4X-(4X-4)+6=0
We get rid of parentheses
4X-4X+4+6=0
We add all the numbers together, and all the variables
10!=0
There is no solution for this equation
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