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X+2/3X=23
We move all terms to the left:
X+2/3X-(23)=0
Domain of the equation: 3X!=0We multiply all the terms by the denominator
X!=0/3
X!=0
X∈R
X*3X-23*3X+2=0
Wy multiply elements
3X^2-69X+2=0
a = 3; b = -69; c = +2;
Δ = b2-4ac
Δ = -692-4·3·2
Δ = 4737
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-69)-\sqrt{4737}}{2*3}=\frac{69-\sqrt{4737}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-69)+\sqrt{4737}}{2*3}=\frac{69+\sqrt{4737}}{6} $
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