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X+2/3X=100
We move all terms to the left:
X+2/3X-(100)=0
Domain of the equation: 3X!=0We multiply all the terms by the denominator
X!=0/3
X!=0
X∈R
X*3X-100*3X+2=0
Wy multiply elements
3X^2-300X+2=0
a = 3; b = -300; c = +2;
Δ = b2-4ac
Δ = -3002-4·3·2
Δ = 89976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{89976}=\sqrt{4*22494}=\sqrt{4}*\sqrt{22494}=2\sqrt{22494}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-2\sqrt{22494}}{2*3}=\frac{300-2\sqrt{22494}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+2\sqrt{22494}}{2*3}=\frac{300+2\sqrt{22494}}{6} $
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