X+2(x-1)=6-(3+2x)

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Solution for X+2(x-1)=6-(3+2x) equation: 



X+2(X-1)=6-(3+2X)

We move all terms to the left:

X+2(X-1)-(6-(3+2X))=0

We add all the numbers together, and all the variables

X+2(X-1)-(6-(2X+3))=0

We multiply parentheses

X+2X-(6-(2X+3))-2=0



We calculate terms in parentheses: -(6-(2X+3)), so:

6-(2X+3)

determiningTheFunctionDomain
-(2X+3)+6

We get rid of parentheses

-2X-3+6

We add all the numbers together, and all the variables

-2X+3

Back to the equation:

-(-2X+3)



We add all the numbers together, and all the variables

3X-(-2X+3)-2=0

We get rid of parentheses

3X+2X-3-2=0

We add all the numbers together, and all the variables

5X-5=0

We move all terms containing X to the left, all other terms to the right

5X=5

X=5/5

X=1

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