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X+2(X+3)=10+2(X+1)
We move all terms to the left:
X+2(X+3)-(10+2(X+1))=0
We multiply parentheses
X+2X-(10+2(X+1))+6=0
We calculate terms in parentheses: -(10+2(X+1)), so:We add all the numbers together, and all the variables
10+2(X+1)
determiningTheFunctionDomain 2(X+1)+10
We multiply parentheses
2X+2+10
We add all the numbers together, and all the variables
2X+12
Back to the equation:
-(2X+12)
3X-(2X+12)+6=0
We get rid of parentheses
3X-2X-12+6=0
We add all the numbers together, and all the variables
X-6=0
We move all terms containing X to the left, all other terms to the right
X=6
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