X+12(x-4)=4x+8(2-x)

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Solution for X+12(x-4)=4x+8(2-x) equation: 



X+12(X-4)=4X+8(2-X)

We move all terms to the left:

X+12(X-4)-(4X+8(2-X))=0

We add all the numbers together, and all the variables

X+12(X-4)-(4X+8(-1X+2))=0

We multiply parentheses

X+12X-(4X+8(-1X+2))-48=0



We calculate terms in parentheses: -(4X+8(-1X+2)), so:

4X+8(-1X+2)

We multiply parentheses

4X-8X+16

We add all the numbers together, and all the variables

-4X+16

Back to the equation:

-(-4X+16)



We add all the numbers together, and all the variables

13X-(-4X+16)-48=0

We get rid of parentheses

13X+4X-16-48=0

We add all the numbers together, and all the variables

17X-64=0

We move all terms containing X to the left, all other terms to the right

17X=64

X=64/17

X=3+13/17

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