X+1/5x=50

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Solution for X+1/5x=50 equation:



X+1/5X=50
We move all terms to the left:
X+1/5X-(50)=0
Domain of the equation: 5X!=0
X!=0/5
X!=0
X∈R
We multiply all the terms by the denominator
X*5X-50*5X+1=0
Wy multiply elements
5X^2-250X+1=0
a = 5; b = -250; c = +1;
Δ = b2-4ac
Δ = -2502-4·5·1
Δ = 62480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{62480}=\sqrt{16*3905}=\sqrt{16}*\sqrt{3905}=4\sqrt{3905}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-250)-4\sqrt{3905}}{2*5}=\frac{250-4\sqrt{3905}}{10} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-250)+4\sqrt{3905}}{2*5}=\frac{250+4\sqrt{3905}}{10} $

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