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X+1/4X=120
We move all terms to the left:
X+1/4X-(120)=0
Domain of the equation: 4X!=0We multiply all the terms by the denominator
X!=0/4
X!=0
X∈R
X*4X-120*4X+1=0
Wy multiply elements
4X^2-480X+1=0
a = 4; b = -480; c = +1;
Δ = b2-4ac
Δ = -4802-4·4·1
Δ = 230384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{230384}=\sqrt{1936*119}=\sqrt{1936}*\sqrt{119}=44\sqrt{119}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-480)-44\sqrt{119}}{2*4}=\frac{480-44\sqrt{119}}{8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-480)+44\sqrt{119}}{2*4}=\frac{480+44\sqrt{119}}{8} $
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