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X+1+2X+5=3(X+2)
We move all terms to the left:
X+1+2X+5-(3(X+2))=0
We add all the numbers together, and all the variables
3X-(3(X+2))+6=0
We calculate terms in parentheses: -(3(X+2)), so:We get rid of parentheses
3(X+2)
We multiply parentheses
3X+6
Back to the equation:
-(3X+6)
3X-3X-6+6=0
We add all the numbers together, and all the variables
=0
X=0/1
X=0
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