X+1+12x=4(1+3x)+10(x-12)

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Solution for X+1+12x=4(1+3x)+10(x-12) equation: 



X+1+12X=4(1+3X)+10(X-12)

We move all terms to the left:

X+1+12X-(4(1+3X)+10(X-12))=0

We add all the numbers together, and all the variables

X+12X-(4(3X+1)+10(X-12))+1=0

We add all the numbers together, and all the variables

13X-(4(3X+1)+10(X-12))+1=0



We calculate terms in parentheses: -(4(3X+1)+10(X-12)), so:

4(3X+1)+10(X-12)

We multiply parentheses

12X+10X+4-120

We add all the numbers together, and all the variables

22X-116

Back to the equation:

-(22X-116)



We get rid of parentheses

13X-22X+116+1=0

We add all the numbers together, and all the variables

-9X+117=0

We move all terms containing X to the left, all other terms to the right

-9X=-117

X=-117/-9

X=+13

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