X+1+1+6x=3(x-4)-(x-4-)

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Solution for X+1+1+6x=3(x-4)-(x-4-) equation: 



X+1+1+6X=3(X-4)-(X-4-)

We move all terms to the left:

X+1+1+6X-(3(X-4)-(X-4-))=0

We add all the numbers together, and all the variables

X+6X-(3(X-4)-(+X))+1+1=0

We add all the numbers together, and all the variables

7X-(3(X-4)-(+X))+2=0



We calculate terms in parentheses: -(3(X-4)-(+X)), so:

3(X-4)-(+X)

We multiply parentheses

3X-(+X)-12

We get rid of parentheses

3X-X-12

We add all the numbers together, and all the variables

2X-12

Back to the equation:

-(2X-12)



We get rid of parentheses

7X-2X+12+2=0

We add all the numbers together, and all the variables

5X+14=0

We move all terms containing X to the left, all other terms to the right

5X=-14

X=-14/5

X=-2+4/5

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