X+(x-2)/3=1+(x-1)/2

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Solution for X+(x-2)/3=1+(x-1)/2 equation: 



X+(X-2)/3=1+(X-1)/2

We move all terms to the left:

X+(X-2)/3-(1+(X-1)/2)=0

We calculate fractions


X+X/()+(-(1+(X-1)*3)/()=0



We calculate terms in parentheses: +(-(1+(X-1)*3)/(), so:

-(1+(X-1)*3)/(

We multiply all the terms by the denominator


-(1+(X-1)*3)



We calculate terms in parentheses: -(1+(X-1)*3), so:

1+(X-1)*3

determiningTheFunctionDomain
(X-1)*3+1

We multiply parentheses

3X-3+1

We add all the numbers together, and all the variables

3X-2

Back to the equation:

-(3X-2)



We get rid of parentheses

-3X+2

Back to the equation:

+(-3X+2)



We get rid of parentheses

X+X/()-3X+2=0

We multiply all the terms by the denominator


X*()+X-3X*()+2*()=0

We add all the numbers together, and all the variables

X+X*()-3X*()=0

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