X+(x+3)+2x-5)=16

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Solution for X+(x+3)+2x-5)=16 equation: 



X+(X+3)+2X-5)=16

We move all terms to the left:

X+(X+3)+2X-5)-(16)=0

We add all the numbers together, and all the variables

3X+(X+3)=0

We get rid of parentheses

3X+X+3=0

We add all the numbers together, and all the variables

4X+3=0

We move all terms containing X to the left, all other terms to the right

4X=-3

X=-3/4

X=-3/4

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