X+(x+3)+(2x-4)=19

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Solution for X+(x+3)+(2x-4)=19 equation:


Simplifying
X + (x + 3) + (2x + -4) = 19

Reorder the terms:
X + (3 + x) + (2x + -4) = 19

Remove parenthesis around (3 + x)
X + 3 + x + (2x + -4) = 19

Reorder the terms:
X + 3 + x + (-4 + 2x) = 19

Remove parenthesis around (-4 + 2x)
X + 3 + x + -4 + 2x = 19

Reorder the terms:
3 + -4 + X + x + 2x = 19

Combine like terms: 3 + -4 = -1
-1 + X + x + 2x = 19

Combine like terms: x + 2x = 3x
-1 + X + 3x = 19

Solving
-1 + X + 3x = 19

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + X + 1 + 3x = 19 + 1

Reorder the terms:
-1 + 1 + X + 3x = 19 + 1

Combine like terms: -1 + 1 = 0
0 + X + 3x = 19 + 1
X + 3x = 19 + 1

Combine like terms: 19 + 1 = 20
X + 3x = 20

Add '-3x' to each side of the equation.
X + 3x + -3x = 20 + -3x

Combine like terms: 3x + -3x = 0
X + 0 = 20 + -3x
X = 20 + -3x

Simplifying
X = 20 + -3x

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