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X+(8/3X-60)=2635
We move all terms to the left:
X+(8/3X-60)-(2635)=0
Domain of the equation: 3X-60)!=0We get rid of parentheses
X∈R
X+8/3X-60-2635=0
We multiply all the terms by the denominator
X*3X-60*3X-2635*3X+8=0
Wy multiply elements
3X^2-180X-7905X+8=0
We add all the numbers together, and all the variables
3X^2-8085X+8=0
a = 3; b = -8085; c = +8;
Δ = b2-4ac
Δ = -80852-4·3·8
Δ = 65367129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8085)-\sqrt{65367129}}{2*3}=\frac{8085-\sqrt{65367129}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8085)+\sqrt{65367129}}{2*3}=\frac{8085+\sqrt{65367129}}{6} $
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