X+(48-x)+(70-x)+(52-x)+(x+4)+(x+4)+(x-4)=190

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Solution for X+(48-x)+(70-x)+(52-x)+(x+4)+(x+4)+(x-4)=190 equation: 



X+(48-X)+(70-X)+(52-X)+(X+4)+(X+4)+(X-4)=190

We move all terms to the left:

X+(48-X)+(70-X)+(52-X)+(X+4)+(X+4)+(X-4)-(190)=0

We add all the numbers together, and all the variables

X+(-1X+48)+(-1X+70)+(-1X+52)+(X+4)+(X+4)+(X-4)-190=0

We get rid of parentheses

X-1X-1X-1X+X+X+X+48+70+52+4+4-4-190=0

We add all the numbers together, and all the variables

X-16=0

We move all terms containing X to the left, all other terms to the right

X=16

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