X+(2x-1)+2(3-x)=(x-2)+(4x+2)

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Solution for X+(2x-1)+2(3-x)=(x-2)+(4x+2) equation: 



X+(2X-1)+2(3-X)=(X-2)+(4X+2)

We move all terms to the left:

X+(2X-1)+2(3-X)-((X-2)+(4X+2))=0

We add all the numbers together, and all the variables

X+(2X-1)+2(-1X+3)-((X-2)+(4X+2))=0

We multiply parentheses

X+(2X-1)-2X-((X-2)+(4X+2))+6=0

We get rid of parentheses

X+2X-2X-((X-2)+(4X+2))-1+6=0



We calculate terms in parentheses: -((X-2)+(4X+2)), so:

(X-2)+(4X+2)

We get rid of parentheses

X+4X-2+2

We add all the numbers together, and all the variables

5X

Back to the equation:

-(5X)



We add all the numbers together, and all the variables

-4X+5=0

We move all terms containing X to the left, all other terms to the right

-4X=-5

X=-5/-4

X=1+1/4

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