X+(2x+40)+3x-50)=15002

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Solution for X+(2x+40)+3x-50)=15002 equation: 



X+(2X+40)+3X-50)=15002

We move all terms to the left:

X+(2X+40)+3X-50)-(15002)=0

We add all the numbers together, and all the variables

4X+(2X+40)=0

We get rid of parentheses

4X+2X+40=0

We add all the numbers together, and all the variables

6X+40=0

We move all terms containing X to the left, all other terms to the right

6X=-40

X=-40/6

X=-6+2/3

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